Calculating the Empirical Formula of a Carbon-Hydrogen Compound with Google SEO Optimization

Calculating the Empirical Formula of a Carbon-Hydrogen Compound with Google SEO Optimization

" "

When dealing with the analysis of chemical compounds, understanding how to determine their empirical formulas is a fundamental skill in chemistry. This article will guide you through the process using a specific example and provide SEO-optimized content to help your website rank better on Google.

" "

Introduction to the Problem

" "

A certain gas compound contains 82.8% carbon and 17.2% hydrogen by mass. The vapour density of this compound is 29. Our task is to find the empirical formula of the compound.

" "

Step-by-Step Methodology

" "

Let's break down the process of calculating the empirical formula into manageable steps:

" "

Step 1: Calculate the Moles of Each Element

" "

To begin, we assume the compound's mass as 100 grams. This simplifies the calculations. From this assumption:

" "" "Carbon (C): 82.8 grams" "Hydrogen (H): 17.2 grams" "" "

Now, we need to convert these grams into moles:

" "

Moles of Carbon 82.8 g / 12.01 g/mol ≈ 6.90 mol

" "

Moles of Hydrogen 17.2 g / 1.01 g/mol ≈ 17.03 mol

" "

Step 2: Find the Simplest Stoichiometric Ratio

" "

Next, we find the simplest whole-number ratio of moles by dividing both values by the smallest number of moles calculated:

" "

Moles of Carbon 6.90 mol / 6.90 mol 1

" "

Moles of Hydrogen 17.03 mol / 6.90 mol ≈ 2.47

" "

Step 3: Convert to Whole Numbers

" "

To convert the ratio to whole numbers, we can multiply both by 2 to simplify the ratio:

" "

Moles of Carbon 1 × 2 2

" "

Moles of Hydrogen 2.47 × 2 ≈ 5

" "

Step 4: Write the Empirical Formula

" "

Based on the calculations, the empirical formula of the compound is:

" "

CH5

" "

Step 5: Verify with Vapour Density

" "

To confirm our empirical formula is correct, we calculate the molar mass:

" "

Molar mass of CH5 (2 × 12.01) (5 × 1.008) 24.02 5.04 29.06 g/mol

" "

This matches the given vapour density of 29 g/mol, confirming our calculations.

" "

SEO-Optimized Content for Google

" "

Incorporating optimal keywords and H-tags can help your content rank higher on Google. Here’s how you might structure your SEO-optimized post:

" "

Calculating the Empirical Formula of a Carbon-Hydrogen Compound

" "

Learn how to calculate the empirical formula of a carbon-hydrogen compound with these step-by-step instructions. Understand the importance of using the given mass percentages, converting them to moles, and finding the simplest ratio.

" "

Understanding the Problem: Carbon and Hydrogen Percentages

" "

A compound is composed of 82.8% carbon and 17.2% hydrogen. We need to find the empirical formula of this compound, which is crucial for understanding its molecular structure.

" "

Critical Steps: Conversions and Calculations

" "

To find the empirical formula, we follow these essential steps:

" "

Step 1: Assumption and Conversion to Moles

" "

Assume the compound's mass is 100 grams, then convert the mass percentages to moles using the molar masses of carbon and hydrogen.

" "

Step 2: Ratio Calculation

" "

Determine the simplest whole-number ratio of moles by dividing by the smallest value.

" "

Step 3: Whole Number Conversion

" "

Convert the decimal values to whole numbers by multiplying by a suitable factor.

" "

Step 4: Determining the Empirical Formula

" "

Write down the empirical formula based on the simplified ratios.

" "

Verification with Vapour Density

" "

Verify the empirical formula using the given vapour density, which confirms the accuracy of the calculated molar mass.

" "

Understanding these steps and calculating the empirical formula can help solve similar problems in chemistry. Make sure to practice these calculations regularly to improve your problem-solving skills.

" "

Keywords: empirical formula, carbon-hydrogen compound, vapour density